f(x)=f(x-1)-f(x-2)怎么证明周期为6?
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f(x)=f(x-1)-f(x-2)怎么证明周期为6?f(x)=f(x-1)-f(x-2)怎么证明周期为6?f(x)=f(x-1)-f(x-2)怎么证明周期为6?f(x)=f(x-1)-f(x-2)f
f(x)=f(x-1)-f(x-2)怎么证明周期为6?
f(x)=f(x-1)-f(x-2)怎么证明周期为6?
f(x)=f(x-1)-f(x-2)怎么证明周期为6?
f(x)=f(x-1)-f(x-2)
f(x-1)=f(x-2)-f(x-3)
f(x)=f(x-1)-f(x-2)=f(x-2)-f(x-3)-f(x-2)=-f(x-3)
f(x+3)=-f(x)
f(x+6)=f[(x+3)+3]=-f(x+3)=-[-f(x)]=f(x)
故f(x)周期为6
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