若 a,b是两个正数,且…………且(a-1)/b +(b-1)/a +1=0,求a、b的取值范围

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若a,b是两个正数,且…………且(a-1)/b+(b-1)/a+1=0,求a、b的取值范围若a,b是两个正数,且…………且(a-1)/b+(b-1)/a+1=0,求a、b的取值范围若a,b是两个正数,

若 a,b是两个正数,且…………且(a-1)/b +(b-1)/a +1=0,求a、b的取值范围
若 a,b是两个正数,且…………
且(a-1)/b +(b-1)/a +1=0,求a、b的取值范围

若 a,b是两个正数,且…………且(a-1)/b +(b-1)/a +1=0,求a、b的取值范围
(a-1)/b+(b-1)/a+1=0
两边同乘ab得:
a^2-a+b^2-b+ab=0
(a+b)^2-2ab-(a+b)+ab=0
ab=(a+b)^2-(a+b)
又:
(a-b)^2≥0
a^2+b^2≥2ab
(a+b)^2≥4ab
ab≤1/4(a+b)^2
所以:ab=(a+b)^2-(a+b)≤1/4(a+b)^2
3/4(a+b)^2-(a+b)≤0
(a+b)[3/4(a+b)-1]≤0
∵a>0,b>0
∴(a+b)>0
∴3/4(a+b)-1≤0
∴(a+b)≤4/3
∴0<a+b≤4/3,

因为(a-1)/b +(b-1)/a +1=0
(a-1)/b+(b-1)/a+1=[a(a-1)+b(b-1)+ab]/ab=0
故有a²+b²-(a+b)+ab=0
(a+b)²-(a+b)-ab=0.......................(1)
(a+b)²-(a+b)=ab≤(a+b)²/4

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因为(a-1)/b +(b-1)/a +1=0
(a-1)/b+(b-1)/a+1=[a(a-1)+b(b-1)+ab]/ab=0
故有a²+b²-(a+b)+ab=0
(a+b)²-(a+b)-ab=0.......................(1)
(a+b)²-(a+b)=ab≤(a+b)²/4
故有1-1/(a+b)≤1/4,1/(a+b)≥1-1/4=3/4,故a+b≤4/3
又由(1)得 (a+b)(a+b-1)=ab
由于a,b都是正数,故必有ab>0,a+b>0,a+b-1>0,由此得a+b>1
故a+b的取值范围为:1

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