已知x2+x-1=0,求x3-2x+2006

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已知x2+x-1=0,求x3-2x+2006已知x2+x-1=0,求x3-2x+2006已知x2+x-1=0,求x3-2x+2006由x^2+x-1=0得x^2+x=1----------(1)x^3

已知x2+x-1=0,求x3-2x+2006
已知x2+x-1=0,求x3-2x+2006

已知x2+x-1=0,求x3-2x+2006
由x^2+x -1=0 得 x^2+x=1 ----------(1)
x^3-2x+2006
=x^3+x^2-x^2-x-x+2006
=x*(x^2+x)-(x^2+x)-x+2006
把（1）式代入上式,即
原x^3-2x+2006=x*1-1-x+2006=2005

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