40x+200-400/x=400,求x
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40x+200-400/x=400,求x40x+200-400/x=400,求x40x+200-400/x=400,求x40x+200-400/x=400x-10/x=5x^2-10=5xx^2-5x
40x+200-400/x=400,求x
40x+200-400/x=400,求x
40x+200-400/x=400,求x
40x+200-400/x=400
x-10/x=5
x^2-10=5x
x^2-5x-10=0
x=(5±√65)/2
反向时相遇则一共400米所以相等关系时A和B的路程之和等于400米 方程是40x 40(x-400÷200)=400 解得x=6 A 遇到了B玩了一会就走了 4 t
40x^2+200x-400=400x
40x²-200x-400=0
x²-5x-10=0
Δ=(-5)^2-4×(-10)=65
x1=(5±√65)/2
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