设函数y=f(x)满足f(x-1)=x^2-2x+3(x

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设函数y=f(x)满足f(x-1)=x^2-2x+3(x设函数y=f(x)满足f(x-1)=x^2-2x+3(x设函数y=f(x)满足f(x-1)=x^2-2x+3(x配方,f(x-1)=(x-1)^

设函数y=f(x)满足f(x-1)=x^2-2x+3(x
设函数y=f(x)满足f(x-1)=x^2-2x+3(x

设函数y=f(x)满足f(x-1)=x^2-2x+3(x
配方,f(x-1)=(x-1)^2+2,x=3
故f^-1(x+1)=-√(x+1-2)=-√(x-1)