根号下(x-1)(x平方-1) (-1

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根号下(x-1)(x平方-1)(-1根号下(x-1)(x平方-1)(-1根号下(x-1)(x平方-1)(-1√[(x-1)*(x²-1)]=√[(x-1)*(x-1)*(x+1)]=√[(x

根号下(x-1)(x平方-1) (-1
根号下(x-1)(x平方-1) (-1

根号下(x-1)(x平方-1) (-1
√[(x-1)*(x²-1)]=√[(x-1)*(x-1)*(x+1)]=√[(x-1)²(x+1)]
因为-1<x<1,
所以x+1>0,x-1<0,
所以原式=(1-x)*√(x+1)

1/(x+1)吧