用换元法解分式方程(x-2/x)^2-2x+4/x=-1
来源：学生作业帮助网 编辑：六六作业网 时间：2024/05/12 09:25:37
用换元法解分式方程(x-2/x)^2-2x+4/x=-1用换元法解分式方程(x-2/x)^2-2x+4/x=-1用换元法解分式方程(x-2/x)^2-2x+4/x=-1令x-2/x=t,则t^2-2t
用换元法解分式方程(x-2/x)^2-2x+4/x=-1
用换元法解分式方程(x-2/x)^2-2x+4/x=-1
用换元法解分式方程(x-2/x)^2-2x+4/x=-1
令x-2/x=t,则t^2-2t+1=0,t=1,所以x-2/x=1,即x^2-x-2=0,解得x=2,或x=-1
(x-2/x)^2-2*(x-2/x)=-1;
令t=x-2/x,
t^2-2t+1=0,t=1,
x-2/x=1,x^2-x-2=(x-2)(x+1)=0,x1=2,x2=-1
关于分式方程的题,分式方程：1-x/x-2 = 1/2-x ( -2)
若关于x的分式方程2x+a/x
用换元法解分式方程x^2-2x+7/x^2-2x=8jjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjj
用换元法解分式方程3x^2+3x=（x^2+x分之2）+1
用换元法解分式方程(x-2/x)^2-2x+4/x=-1
用换元法解分式方程X^2+1/x - 2（x+1/x）-1=0
请问分式方程x+2/|x|-2怎么解?
怎么解这道分式方程.5/x=5/x+2
解分式方程：3/x=5/x+2
解分式方程!80/x=100/x+2
80/x=80/2x+5 分式方程,
解分式方程x-6/x+2-1=0
分式方程 36/x*12*2x=1154
用换元法解分式方程(2x-1)+x/(2x-1)=2
x/(x-2)+(x+1)/(x-6)=2x/(x-3) 解分式方程
x/2是不是分式
x^2/x是不是分式?
解分式方程:x-2/x+2=x+2/x-2+16/x平方-4