f(x)=lnx+∫(1,e)f(x)dx-f '(1) ,求f(x)

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f(x)=lnx+∫(1,e)f(x)dx-f''(1),求f(x)f(x)=lnx+∫(1,e)f(x)dx-f''(1),求f(x)f(x)=lnx+∫(1,e)f(x)dx-f''(1),求f(x)f

f(x)=lnx+∫(1,e)f(x)dx-f '(1) ,求f(x)
f(x)=lnx+∫(1,e)f(x)dx-f '(1) ,求f(x)

f(x)=lnx+∫(1,e)f(x)dx-f '(1) ,求f(x)
f(x) = lnx + ∫(1→e) f(x) dx - f'(1)
f'(x) = 1/x ==> f'(1) = 1
f(x) = lnx + A - 1,A = ∫(1→e) f(x) dx
A = ∫(1→e) lnx dx + (A - 1)∫(1→e) dx
A = [xlnx - x] |(1→e) + (A - 1)(e - 1)
A = (e - e) - (0 - 1) + Ae + 1 - e - A
A(2 - e) = 2 - e
A = 1

f(x) = lnx