已知α是第二象限角,则sin(α-2π)/√[1-cos^2(-α)]+2√[1-cos^2(π/2+α)]/sin(α-3π/2)

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已知α是第二象限角,则sin(α-2π)/√[1-cos^2(-α)]+2√[1-cos^2(π/2+α)]/sin(α-3π/2)已知α是第二象限角,则sin(α-2π)/√[1-cos^2(-α)

已知α是第二象限角,则sin(α-2π)/√[1-cos^2(-α)]+2√[1-cos^2(π/2+α)]/sin(α-3π/2)
已知α是第二象限角,则sin(α-2π)/√[1-cos^2(-α)]+2√[1-cos^2(π/2+α)]/sin(α-3π/2)

已知α是第二象限角,则sin(α-2π)/√[1-cos^2(-α)]+2√[1-cos^2(π/2+α)]/sin(α-3π/2)
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