求cosx+cos(120-x)+(120+x)的值快

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求cosx+cos(120-x)+(120+x)的值快求cosx+cos(120-x)+(120+x)的值快求cosx+cos(120-x)+(120+x)的值快=cosx+cos120cosx+si

求cosx+cos(120-x)+(120+x)的值快
求cosx+cos(120-x)+(120+x)的值

求cosx+cos(120-x)+(120+x)的值快
=cosx+cos120cosx+sinxsin120+cos120cosx-sinxsin120
=cosx+2cos120cosx
=cosx+2*(-cos60)cosx
=cosx-cosx=0

原式=cosx+cos120cosx+sin120sinx+cos120cosx-sin120sinx
=cosx+2cos120cosx
=cosx+2×(-1/2)cosx
=0