用换元法求不定积分,1/(1+x)(x+2),答案为ln|(x+1)/(x+2)|+1/(x+2)+c,

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用换元法求不定积分,1/(1+x)(x+2),答案为ln|(x+1)/(x+2)|+1/(x+2)+c,用换元法求不定积分,1/(1+x)(x+2),答案为ln|(x+1)/(x+2)|+1/(x+2

用换元法求不定积分,1/(1+x)(x+2),答案为ln|(x+1)/(x+2)|+1/(x+2)+c,
用换元法求不定积分,1/(1+x)(x+2),答案为ln|(x+1)/(x+2)|+1/(x+2)+c,

用换元法求不定积分,1/(1+x)(x+2),答案为ln|(x+1)/(x+2)|+1/(x+2)+c,
1/(1+x)(x+2)=1/(x+1)-1/(x+2)
剩下的就很简单的了呵 你的答案是不正确的,
应该是:ln|(x+1)/(x+2)|+c