求x^2-y^2=1979的整数解

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求x^2-y^2=1979的整数解求x^2-y^2=1979的整数解求x^2-y^2=1979的整数解x^2-y^2=1979(x+y)(x-y)=1979因1979是质数,所以当x+y=1979,x

求x^2-y^2=1979的整数解
求x^2-y^2=1979的整数解

求x^2-y^2=1979的整数解
x^2-y^2 = 1979
(x+y)(x-y) = 1979
因1979是质数,所以
当 x+y = 1979 ,x-y = 1 时,x=990 ,y=989
当 x+y = 1 ,x-y = 1979 时,x=990 ,y=-989
当 x+y = -1979 ,x-y = -1 时,x=-990 ,y=-989
当 x+y = -1 ,x-y = -1979 时,x=-990 ,y=989

x=990,y=989