√3sinA+cosA=2sin(A+π/6) 怎么变换过来的
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/01 07:12:19
√3sinA+cosA=2sin(A+π/6)怎么变换过来的√3sinA+cosA=2sin(A+π/6)怎么变换过来的√3sinA+cosA=2sin(A+π/6)怎么变换过来的√3sinA+cos
√3sinA+cosA=2sin(A+π/6) 怎么变换过来的
√3sinA+cosA=2sin(A+π/6) 怎么变换过来的
√3sinA+cosA=2sin(A+π/6) 怎么变换过来的
√3sinA+cosA
=2(sinA*√3/2+cosA*1/2)
=2(sinA*cosπ/6+cosA*sinπ/6)
=2sin(A+π/6)
辅助角
√3sinA+cosA
=2[(√3/2)sinA+(1/2)cosA]
=2[cos(π/6)sinA+sin(π/6)cosA]
=2sin(A+π/6)
√3sinA+cosA
=2[sinAcos(π/6)+cosAsin(π/6)
=2sin(A+π/6)
√3sinA+cosA=2[(√3/2)sinA+(1/2)cosA]=2[cos(π/6)sinA+sin(π/6)cosA]=2sin(A+π/6)
已知(sina+cosa)/(sina-cosa)=3 则2sin'a+(sina-cosa)'=?
为啥sina+cosa=√2sin(a+π/4)
sinA=3sin(2π/3-A) SINA=?sinA=3sin(2π/3-A) SINA=?答案是-3√3cosA
已知tan(π-a)=2,求值:(1)2sin+2cosa/7sina+cosa(2)sina*cosa(3)4cosa^2+3sina^2
sina=2cosa,求(1)3sina+2cosa(2)sin²a+sina×cosa+3
sin(a+kπ)=2cos[a+(k+1)π].求5cosa+3sina/4sina-2cosa
sin(a+kπ)=2cos[a+(k+1)π].求5cosa+3sina/4sina-2cosa
设(sina)^2-sina-2(cosa)^2=0,求sin(a-3π/2)
为什么:sinA -√3cosA=2sin(a-π/3)?
sina +-√3cosa=2sin(a +-π /3)是怎么推出来的,
√3sinA+cosA=2sin(A+π/6) 怎么变换过来的
已知tana=-3,求sina+2cosa/cosa-3sina和sin^2a-sinacosa
已知(sina+cosa)/(sina-cosa)=2,则:(3sina+cosa)/(2sina+3cosa)=?sin^2a-2sinacosa+1=?
已知sina+cosa/sina-cosa=2,计算下列各式的值(1)3sina+cosa/2sina+3cosa(2)sin^a-2sinacosa+1.
已知tana=3,求下列各式的值 1.sina+cosa/sina-cosa 2.sina.cosa 3.sin^2 a+sina.cosa
已知sin=-3/5,那么(cosa+sina/cosa-sina)+(cosa-sina/cosa+sina)(a代表角,
三角函数!化简!√3SinA-CosA-1=0怎么从√3SinA-CosA-1=0到 Sin(A-π/6)=1/2
若sinA+cosA/sinA-cosA=2,则sin(A-5π)*sin(7π/2-A)等于?