化简(n+1)(n+2)(n+3)
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化简(n+1)(n+2)(n+3)化简(n+1)(n+2)(n+3)化简(n+1)(n+2)(n+3)设n+2=x所以(n+1)(n+2)(n+3)=(x-1)*x*(x+1)=(x^2-1)*x=x
化简(n+1)(n+2)(n+3)
化简(n+1)(n+2)(n+3)
化简(n+1)(n+2)(n+3)
设n+2=x
所以(n+1)(n+2)(n+3)
=(x-1)*x*(x+1)
=(x^2-1)*x
=x^3-x
将n+2=x代入,得n^3+3n^2*2+3n*2^2+2^3-n-2
=n^3+6n^2+12n-n-2
=n^3+6n^2+11n-2
[3n(n+1)+n(n+1)(2n+1)]/6+n(n+2)化简
[3n(n+1)+n(n+1)(2n+1)]/6+n(n+2)化简
化简n分之n-1+n分之n-2+n分之n-3+.+n分之1
化简n分之n-1+n分之n-2+n分之n-3+.+n分之1
化简(n+1)(n+2)(n+3)
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