∫sin(3x)cos(4x)dx=
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∫sin(3x)cos(4x)dx=∫sin(3x)cos(4x)dx=∫sin(3x)cos(4x)dx=∫sin(3x)cos(4x)dx=1/2∫[sin(3x+4x)+sin(3x-4x)]d
∫sin(3x)cos(4x)dx=
∫sin(3x)cos(4x)dx=
∫sin(3x)cos(4x)dx=
∫sin(3x)cos(4x)dx
=1/2∫[sin(3x+4x)+sin(3x-4x)]dx
=1/2∫[sin(7x)+sin(-x)]dx
=-1/14cos7x+1/2sinx+C
用积化和差公式
原式=1/2∫(sin7x-sinx)dx
=-1/14*cos7x+1/2*cosx+C
∫cos^4x/sin^3x dx=?
∫sin(3x)cos(4x)dx=
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定积分∫(-π/2,π/2)(cos^4x+sin^3x)dx=
-π/3 ∫(sin x+cos x)dx=? -π/4
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