含步骤```设y= 1+1n(1-x) 求y'(0)1-x

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含步骤```设y=1+1n(1-x)求y''(0)1-x含步骤```设y=1+1n(1-x)求y''(0)1-x含步骤```设y=1+1n(1-x)求y''(0)1-xy''=(1-x)/(1+x)y''(0)

含步骤```设y= 1+1n(1-x) 求y'(0)1-x
含步骤```
设y= 1+1n(1-x) 求y'(0)
1-x

含步骤```设y= 1+1n(1-x) 求y'(0)1-x
y'=(1-x)/(1+x)
y'(0)=(1-0)/(1+0)=1