函数y=2sin(2x+π/4)的单调递增区间怎么求

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函数y=2sin(2x+π/4)的单调递增区间怎么求函数y=2sin(2x+π/4)的单调递增区间怎么求函数y=2sin(2x+π/4)的单调递增区间怎么求-π/2+2kπ≤2x+π/4≤π/2+2k

函数y=2sin(2x+π/4)的单调递增区间怎么求
函数y=2sin(2x+π/4)的单调递增区间怎么求

函数y=2sin(2x+π/4)的单调递增区间怎么求
-π/2+2kπ≤2x+π/4≤π/2+2kπ
-3π/4≤2x≤π/4
-3π/8≤x≤π/8
单调区间为[-3π/8,π/8]

2kπ-π/2<2x+π/4<2kπ+π/2递增 ,整理得kπ-3π/82kπ+π/2<2x+π/4<2kπ+3π/2递减 , 整理得kπ+π/8