已知数列满足a1=1,根号an-1-根号an=根号anan-1,求an

来源:学生作业帮助网 编辑:六六作业网 时间:2024/05/11 12:20:32
已知数列满足a1=1,根号an-1-根号an=根号anan-1,求an已知数列满足a1=1,根号an-1-根号an=根号anan-1,求an已知数列满足a1=1,根号an-1-根号an=根号anan-

已知数列满足a1=1,根号an-1-根号an=根号anan-1,求an
已知数列满足a1=1,根号an-1-根号an=根号anan-1,求an

已知数列满足a1=1,根号an-1-根号an=根号anan-1,求an
√[a(n-1)]-√[an]=√[ana(n-1)]
两边同时除以√[ana(n-1)]
得:1/√[an]-1/√[an(n-1)]=1
令bn=1/√[an]
则bn-b(n-1)=1,b1=1
∴bn是以首相b1=1,公差d=1的等差数列
故bn=n
所以1/√[an]=n
得 an=1/n²
答案:an=1/n²

则bn-b(n-1)=1,b1=1
∴bn是以首相b1=1,公差d=1的等差数列
故bn=n
所以1/√[

已知数列满足a1=1,根号an-1-根号an=根号anan-1,求an 已知数列an满足a1=0,an+1=an-根号3/根号3an+1,则a2012= 已知数列an满足a1=1,1/an+1=根号1/an^2+2,an>0,求an 已知数列{an}满足a1=1,且对任意n属于自然数都有1/根号a1+1/根号a2+...+1/根号an=1 已知数列{an}满足a1=0,an+1=(an-根号3)/(根号3an+1) (n属于N+),则该数列中a20=____ 已知数列满足a1=1,根号a(n-1)-根号an=根号an*a(n-1),求an 已知数列{an}满足a1=1,1/an+1=根号1/an62+2,an>0,求an是根号【1/(an^2+2)] 已知数列{an}满足an>0,a1=3 根号下[a(n+1)]=(根号下an)+1 (n属于N*) 则an=?如题. 已知数列an满足a1=0 an+1=an-根号3/根号3an+1 则a2010的值为 已知数列 {an}满足a1=0,an+1=(an-根号3)/(根号3an+1),则a20的值为 已知数列an满足 a1=0,an+1=根号3倍的an再加1 分之an-根号3,n属于n*则a20等于? 已知数列{an}满足,a1=2,a(n+1)=3根号an,求通项an数列{an}满足:an>0,且根号下Sn=an+1/4,求通项an 已知数列{an}满足an^2=a(n+1)an-1(n>=1),且a1=根号2,则与根号(a2005)最接近的自然数是 已知数列{an}满足a1=0 a(n+1)=(an-根号3)/(根号3an+1) (n属于N*),则a20=? 已知数列{an}满足A1=0,A(N+1)=AN减去根号三/根号三AN加1.求A2,A3,A4,A5,A6N为正整数 已知数列{an}满足A1=0,A(N+1)=AN减去根号三/根号三AN加1.求通项公式和A20 数列an满足an+1=根号(an^2+1)+an,a1=a>0,求an通项公式 已知数列an,满足a1=1,an=an-1+1/an-1,求证;对任意,不等式根号2n-1