∫(3x+2)/(x(x+1)^3)dx
来源：学生作业帮助网 编辑：六六作业网 时间：2024/05/15 18:27:03
∫(3x+2)/(x(x+1)^3)dx∫(3x+2)/(x(x+1)^3)dx∫(3x+2)/(x(x+1)^3)dx原式=∫[2/x-2/(x+1)-2/(x+1)²+1/(x+1)&s
∫(3x+2)/(x(x+1)^3)dx
∫(3x+2)/(x(x+1)^3)dx
∫(3x+2)/(x(x+1)^3)dx
原式=∫[2/x-2/(x+1)-2/(x+1)²+1/(x+1)³]dx
=2ln│x│-2ln│x+1│+2/(x+1)-(1/2)/(x+1)²+C (C是积分常数)
=2ln│x/(x+1)│+2/(x+1)-(1/2)/(x+1)²+C.
∫x^3/1+x^2 dx
∫(x-1)^2/x^3 dx
∫(X^3)/(1+X^2)dx
x-9/[(根号)x]+3 dx ∫ x+1/[(根号)x] dx ∫ [（3-x^2）]^2 dx
∫(x^3-x^2+x+1)/(x^2+1) dx∫(x+4)/(x^2-x-2) dx
∫x^3/(x^8-2) dx∫(x^3-1)/(x^2+1) dx
∫(3x+2)/(x(x+1)^3)dx
∫(3x+2)/x(x+1)^3 dx
∫（x^3 -x)(3x^2-1)dx
∫(3x^4+x^2)/(x^2+1)dx
∫(e^x+3x^2+(2/x)-1)dx
∫x/(3+4x+x^2)^1/2dx
求不定积分∫(x^2-3x)/(x+1)dx
∫[(x^2-x+6)/(x^3+3x)]dx
∫1/x(1+x^3)dx
∫x+1／(x-1)^3dx
∫dx/x(2x+3)^2
求∫x/(1+x)^3 dx