设函数f(x)=-1/3x^3+2ax^2+1/3a(0
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设函数f(x)=-1/3x^3+2ax^2+1/3a(0设函数f(x)=-1/3x^3+2ax^2+1/3a(0设函数f(x)=-1/3x^3+2ax^2+1/3a(0由f(x)=-1/3x^3+2a
设函数f(x)=-1/3x^3+2ax^2+1/3a(0
设函数f(x)=-1/3x^3+2ax^2+1/3a(0
设函数f(x)=-1/3x^3+2ax^2+1/3a(0
由f(x)=-1/3x^3+2ax^2+1/3a(0
令 f'(x)=-x^2+4ax=0,解得x1=0,x2=4a
则(1)x>=4a时,f'(x)<0,f(x)为减函数
(2)0
(3)x<=0时,f'(x)<0,f(x)为减函数
若a<=x<=2时
则(1)当1>a>1/2时,此时0
上述a的范围的并集即为所求：1/2>=a>=(根号2)/8
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