求函数xcosy=sin(x+y)的导数

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求函数xcosy=sin(x+y)的导数求函数xcosy=sin(x+y)的导数求函数xcosy=sin(x+y)的导数对x求导1*cosy+x*(-siny)*y''=cos(x+y)*(x+y)''c

求函数xcosy=sin(x+y)的导数
求函数xcosy=sin(x+y)的导数

求函数xcosy=sin(x+y)的导数
对x求导
1*cosy+x*(-siny)*y'=cos(x+y)*(x+y)'
cosy-xsiny*y'=cos(x+y)(1+y')=cos(x+y)+cos(x+y)*y'
所以y'=[cosx-cos(x+y)]/[cos(x+y)+xsiny]

cosy+x(-siny)y`=cos(x+y)(1+y`)
cosy-xsinyy`=cos(x+y)+y`cos(x+y)
cosy-cos(x+y)=y`cos(x+y)+xsinyy`
y`=[cosy-cos(x+y)]/[cos(x+y)+xsiny]

整理得xcosy-sin(x y)=0
得dy/dx=-Fx/Fy
=-[cosy-cos(x y)]/[-xsiny-cos(x y)]
=[cosy-cos(x y)]/[xsiny cos(x y)]j13815949909m如果我回答的好请给我分谢谢BDDC

列示为:cosy+x(-siny)y`=cos(x+y)(1+y`)
cosy-xsinyy`=cos(x+y)+y`cos(x+y)
cosy-cos(x+y)=y`cos(x+y)+xsinyy`
y`=[cosy-cos(x+y)]/[cos(x+y)+xsiny]