已知=ln[x+根号(x^2+1)],求二阶导数d^2y/dx^2

来源:学生作业帮助网 编辑:六六作业网 时间:2024/05/17 19:17:29
已知=ln[x+根号(x^2+1)],求二阶导数d^2y/dx^2已知=ln[x+根号(x^2+1)],求二阶导数d^2y/dx^2已知=ln[x+根号(x^2+1)],求二阶导数d^2y/dx^2y

已知=ln[x+根号(x^2+1)],求二阶导数d^2y/dx^2
已知=ln[x+根号(x^2+1)],求二阶导数d^2y/dx^2

已知=ln[x+根号(x^2+1)],求二阶导数d^2y/dx^2
y'=(1+x/√(1+x^2))/(x+√(1+x^2))
=1/√(1+x^2)
y''=-x/(1+x^2)^(3/2)