(lg2)^2+lg2*lg5+(lg5)^2=
来源：学生作业帮助网 编辑：六六作业网 时间：2024/05/10 18:04:07
(lg2)^2+lg2*lg5+(lg5)^2=(lg2)^2+lg2*lg5+(lg5)^2=(lg2)^2+lg2*lg5+(lg5)^2=(lg2)^2+lg2*lg5+(lg5)^2=2(lg
(lg2)^2+lg2*lg5+(lg5)^2=
(lg2)^2+lg2*lg5+(lg5)^2=
(lg2)^2+lg2*lg5+(lg5)^2=
(lg2)^2+lg2*lg5+(lg5)^2
=2(lg2) + lg(2+5)+2(lg5)
=2(lg2+lg5)+lg7
=2lg(2×5)+lg7
=2lg10+lg7
=2+lg7
lg5+lg5*lg2+lg2*lg2
lg2(1+lg5)+(lg5)^2
计算：(lg5)^2 +lg2 *lg5
(lg5)^2+lg5.lg2=
2lg2（lg2+lg5)+2lg5得数
(lg2)^2+lg2*lg5+(lg5)^2=
lg2*lg50+lg5*lg20-2lg5*lg2
(lg5)平方+2*lg5*lg2+(lg2)平方
(lg2)^2+lg5*lg20
(lg2)^2+lg20*lg5
（lg5)^2+lg2*lg50
3+lg5+(lg2)^2
2lg5*lg2=
=(lg5)^2+lg2×lg5+lg2 =lg5×(lg5+lg2)+lg2麻烦问一下,这是咋做的
lg5(1-lg5)+2lg5根号2+lg2(1-lg5)
lg2*lg2+lg5-lg2=?
lg2^2+lg2*lg5+lg5=lg2(lg2+lg5)+lg5这个过程中,lg2的平方怎么没了?
(lg^2)2+lg2*lg5+lg5