若x^2+7x-8=0,则x-(8/x)=

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若x^2+7x-8=0,则x-(8/x)=若x^2+7x-8=0,则x-(8/x)=若x^2+7x-8=0,则x-(8/x)=x^2+7x-8=0(x-1)(x+8)=0x1=1x2=-8x-(8/x

若x^2+7x-8=0,则x-(8/x)=
若x^2+7x-8=0,则x-(8/x)=

若x^2+7x-8=0,则x-(8/x)=
x^2+7x-8=0
(x-1)(x+8)=0
x1=1 x2=-8
x-(8/x)=1-(8/1)=-7
x-(8/x)=-8-(8/-8)=-7