(x-1/2)(2x+1)(2x^2+1/2)(4x^4+1/4)(16x^6+1/16)/(256x^16+1/256)=?

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(x-1/2)(2x+1)(2x^2+1/2)(4x^4+1/4)(16x^6+1/16)/(256x^16+1/256)=?(x-1/2)(2x+1)(2x^2+1/2)(4x^4+1/4)(16x

(x-1/2)(2x+1)(2x^2+1/2)(4x^4+1/4)(16x^6+1/16)/(256x^16+1/256)=?
(x-1/2)(2x+1)(2x^2+1/2)(4x^4+1/4)(16x^6+1/16)/(256x^16+1/256)=?

(x-1/2)(2x+1)(2x^2+1/2)(4x^4+1/4)(16x^6+1/16)/(256x^16+1/256)=?
第五个括号疑为 (16x^8+1/16) 即其中 x 的指数为 8 ,而非 6.
解法:把第二个括号与第一个括号换个位置,然后变为2(x + 1/2),
反复用 (a+b)(a-b)=a²-b² 即可.
大概用四次吧