∫[sin(2x+л/4]^-2 dx

∫ 4/sin^2x dx ∫[sin(2x+л/4]^-2 dx ∫x/sin^2(x) dx ∫sin(x) cos^2(x)dx ∫dx/cos^2X+4sin^2X 求微积分 ∫sin^2(x)cos^4(x) dx ∫x^2sin(4x)dx 怎么算啊 用换元法计算不定积分∫x sin[(x^2)+4] dx ∫[1/(sin^2(x)cos^4(x)]dx 求解∫1/(cos^4(x)sin^2(x))dx ∫sin^2x/(1+sin^2x )dx求解, ∫sin(6x)sin(2x)dx=? ∫(2/sin^2x)dx= ∫(1-sin^2( x/2))dx 求∫ sin^2 x/2 dx .. 求不定积分：∫sin(x^2)dx 求不定积分∫sin(x/2)dx ∫[(sin^2)x]dx求不定积分