lim(n→∞)4^n/(4^(n+1)+(a+1)^n)=1/4,则a的取值范围是还没学过lim,所以不太懂.

求极限 lim(n→∞) tan^n (π/4 + 2/n) lim(n→∞)tan^n(π/4+2/n) =lim(n→∞)[(tan(π/4)+tan(2/n))/(1-tan(π/4)tan(2/n))]^n =lim(n→∞)[(1+tan(2/n))/(1-tan(2/n))]^n =lim(n→∞)(1+tan(2/n))^n/(1-tan(2/n))^n (1) 因为 lim(n→∞)(1+tan(2/n) lim(n→∞) 1/(n+1)-2/(n+1)+3/(n+1)-4/(n+1)+...+[(2n-1)/(n+1)]-[(2n)/(n-1)]求极限 大一微积分解答：lim(n→+∞)（2^n+4^n+6^n+8^n）^1/n=? 用数列极限证明lim(n→∞)(n^-2)/(n^+n+1)=1中证明如下:lim(n→∞)3n+1/5n-4 求当n→∞,Lim(1+2+3+4+……+(n-1)+n)/n lim(n+3)(4-n)/(n-1)(3-2n) lim(n^3+n)/(n^4-3n^2+1) lim(n→∞) (3^n-4^n)/(3^n+2×4^n),请计算, lim {（-4）^n+5^n}/{4^(n+1) + 5^(n+1)} n→无限 一道极限题,lim[n^2(2n+1)]/(n^3+n+4)n->∞ 求数分大神lim(n→∞)∑(k=1→n)√((n+k)(n+k+1)/n^4) lim n→∞ [(n+1)^4/5^(n+1)]/[n^4/5^n]为何等于1/5, lim((5^n-4^(n-1))/((5^(n+1)+3^(n+2)) n→∞时的极限是多少? 高数题:lim(n→∞)(1+2∧n+3∧n+4∧n)∧ 1/n=? 求lim(n→∞)时[5^n-4^(n-1)]/5^(n+1)+3^(n+2) n→∞ lim[1+1/(1+2n)+1/(2+2n)+1/(3+2n)+1/(4+2n).+1/(n+2n)]= lim （n→∞) [(-2)^(n+1)/(1-2+4+...+(-2)^n) lim （n→∞) [(-2)^(n+1)/(1-2+4+...+(-2)^n),