已知丨x+2y+1丨+( 2x-y-2)^2=0,求(2x-y)^2-2(2x-y)(2x-y)+(2x+y)^2的值

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已知丨x+2y+1丨+(2x-y-2)^2=0,求(2x-y)^2-2(2x-y)(2x-y)+(2x+y)^2的值已知丨x+2y+1丨+(2x-y-2)^2=0,求(2x-y)^2-2(2x-y)(

已知丨x+2y+1丨+( 2x-y-2)^2=0,求(2x-y)^2-2(2x-y)(2x-y)+(2x+y)^2的值
已知丨x+2y+1丨+( 2x-y-2)^2=0,求(2x-y)^2-2(2x-y)(2x-y)+(2x+y)^2的值

已知丨x+2y+1丨+( 2x-y-2)^2=0,求(2x-y)^2-2(2x-y)(2x-y)+(2x+y)^2的值
丨x+2y+1丨+( 2x-y-2)^2=0
所以:
x+2y+1=0
2x-y-2=0
那么
x+2y=-1
2x-y=2
带入
(2x-y)^2-2(2x-y)(2x-y)+(2x+y)^2
=2^2-2×2^2+(-1)^2
=-3

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