∫上0下e-1 ln(x+1)dx

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∫上0下e-1ln(x+1)dx∫上0下e-1ln(x+1)dx∫上0下e-1ln(x+1)dx原式=∫(0~(e-1))ln(x+1)d(x+1)=(x+1)ln(x+1)(0~(e-1))-∫(0

∫上0下e-1 ln(x+1)dx
∫上0下e-1 ln(x+1)dx

∫上0下e-1 ln(x+1)dx
原式=∫(0~(e-1))ln(x+1)d(x+1)
=(x+1)ln(x+1)(0~(e-1))-∫(0~(e-1))(x+1)dln(x+1)
=(x+1)ln(x+1)(0~(e-1))-x(0~(e-1))
=-e+e-1
=-1