tan(arcsin(1/3)+arccos(-1/5))求值
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tan(arcsin(1/3)+arccos(-1/5))求值tan(arcsin(1/3)+arccos(-1/5))求值tan(arcsin(1/3)+arccos(-1/5))求值设sina=1
tan(arcsin(1/3)+arccos(-1/5))求值
tan(arcsin(1/3)+arccos(-1/5))求值
tan(arcsin(1/3)+arccos(-1/5))求值
设sina=1/3 cosb=-1/5
则cosa=√(1-sin²a)=2√2/3
sinb=√(1-cos²b)=2√6/5
所以tana=sina/cosa=√2/4
tanb=sinb/cosb=-2√6
故tan(arcsin(1/3)+arccos(-1/5))
=tan(a+b)
=(tana+tanb)/(1-tana*tanb)
=(√2/4-2√6)/(1+√2/4*2√6)
=(√2-8√6)/(4+4√3)
=(9√6-25√2)/8
tan[arcsin(-1/3)]
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tan(arcsin(1/3)+arccos(-1/5))求值
tan[arcsin(-3/5)]=怎么考虑
计算 tan【arcsin（-1/3）】=?cos（arcsin3/5）=?
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