limx趋向于兀sin(x-兀)/x-兀.用洛必达法则求极限

来源:学生作业帮助网 编辑:六六作业网 时间:2024/06/06 23:43:44
limx趋向于兀sin(x-兀)/x-兀.用洛必达法则求极限limx趋向于兀sin(x-兀)/x-兀.用洛必达法则求极限limx趋向于兀sin(x-兀)/x-兀.用洛必达法则求极限lim(x->π)s

limx趋向于兀sin(x-兀)/x-兀.用洛必达法则求极限
limx趋向于兀sin(x-兀)/x-兀.用洛必达法则求极限

limx趋向于兀sin(x-兀)/x-兀.用洛必达法则求极限
lim(x->π) sin(x-π)/(x-π ) (0/0)
=lim(x->π) cos(x-π)
=1