f(x)=f'(1)e^(x-1)-f(0)x+1/2 x^2,求f'(x)
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f(x)=f''(1)e^(x-1)-f(0)x+1/2x^2,求f''(x)f(x)=f''(1)e^(x-1)-f(0)x+1/2x^2,求f''(x)f(x)=f''(1)e^(x-1)-f(0)x+1/
f(x)=f'(1)e^(x-1)-f(0)x+1/2 x^2,求f'(x)
f(x)=f'(1)e^(x-1)-f(0)x+1/2 x^2,求f'(x)
f(x)=f'(1)e^(x-1)-f(0)x+1/2 x^2,求f'(x)
令x=0,得f(0)=f'(1)/e
对原式两边求导得f'(x)=f'(1)e^(x-1)-f(0)+x,令x=1并把f(0)=f'(1)/e带入得f'(1)=f'(1)-f'(1)/e+1
则f'(1)=e,f(0)=1,带入f'(x)=f'(1)e^(x-1)-f(0)+x得f'(x)=e^x-1+x
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