f(2x+1)=e^x,求f(x)

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f(2x+1)=e^x,求f(x)f(2x+1)=e^x,求f(x)f(2x+1)=e^x,求f(x)令a=2x+1x=(a-1)/2所以f(a)=e^[(a-1)/2]所以f(x)=e^[(x-1)

f(2x+1)=e^x,求f(x)
f(2x+1)=e^x,求f(x)

f(2x+1)=e^x,求f(x)
令a=2x+1
x=(a-1)/2
所以f(a)=e^[(a-1)/2]
所以f(x)=e^[(x-1)/2]

令t=2x+1, x=(t-1)/2
f(t)=e^[(t-1)/2]
即f(x)=e^[(x-1)/2]

令t=2x+1,则x=(t-1)/2,所以f(x)=e^(t-1)/2